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The area of a square is 15 more than 8 times its side. If the side is x, which equation is correct?

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Answer and explanation

Correct answer: \(x^2-8x-15=0\)

For a square with side x the area is \(x^2\). The statement says the area is 15 more than 8 times the side, so \(x^2=8x+15\). Bringing all terms to one side gives \(x^2-8x-15=0\), so option A is correct. Distractors fail for clear reasons: C swaps the coefficients (places 15 with 8) and thus misrepresents the given relation; B has wrong signs (+) so it does not match the sentence. Exam tip: Always translate the English sentence into a mathematical equality (area = ...) before rearranging to standard quadratic form.

Related tags

Quadratic-EquationsWord-ProblemSquare-AreaAlgebra

Frequently asked questions

What is the correct answer to this question?

\(x^2-8x-15=0\)

Why is this the correct answer?

For a square with side x the area is \(x^2\). The statement says the area is 15 more than 8 times the side, so \(x^2=8x+15\). Bringing all terms to one side gives \(x^2-8x-15=0\), so option A is correct. Distractors fail for clear reasons: C swaps the coefficients (places 15 with 8) and thus misrepresents the given relation; B has wrong signs (+) so it does not match the sentence. Exam tip: Always translate the English sentence into a mathematical equality (area = ...) before rearranging to standard quadratic form.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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