In ((k-2)x^2+2kx+(k+3)=0), with (k\neq2), what is the correct condition for real roots?

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Correct answer: (k\geq\frac{3}{2})

Here (D=(2k)^2-4(k-2)(k+3)=4(6-k)). For real roots we need (k\leq6), so check simplification carefully.

What is the correct answer to this question?

(k\geq\frac{3}{2})

Why is this the correct answer?

Here (D=(2k)^2-4(k-2)(k+3)=4(6-k)). For real roots we need (k\leq6), so check simplification carefully.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Nature of Roots.

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