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The hypotenuse of a right triangle is 109 cm. One leg is 19 cm longer than the other leg. What is the length of the shorter leg?

Answer and explanation

Correct answer: \(\frac{\sqrt{23401}-19}{2}\) cm

Let the shorter leg be \(x\) cm. Then the longer leg is \(x+19\) cm. By the Pythagorean theorem, \(x^2+(x+19)^2=109^2\), which simplifies to \(x^2+19x-5760=0\). Its positive solution is \(x=\frac{\sqrt{23401}-19}{2}\approx66.99\) cm, so option A is correct. Option B is incorrect because legs of 60 cm and 79 cm do not produce a hypotenuse of 109 cm. Exam tip: for a length problem, reject the negative root and verify the result using the Pythagorean relation.

Related tags

Quadratic EquationsRight TrianglePythagorean TheoremWord ProblemsIrrational RootsWord Problems And ApplicationsMathematicsClass 10 Mcq

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