यदि \(x\neq 0\) हो, तो (\left\(2x^{-3}\right\)^{-2}\cdot x^{-1}) का सरल रूप क्या होगा?
If \(x\neq 0\), what is the simplified form of (\left\(2x^{-3}\right\)^{-2}\cdot x^{-1})?
Explanation opens after your attempt
Correct Answer
A. \(\frac{x^{5}}{4}\)
Concept
Here (\left\(2x^{-3}\right\)^{-2}=2^{-2}x^{6}=\frac{x^{6}}{4}), so multiplying by \(x^{-1}\) gives \(\frac{x^{5}}{4}\). In exams, first convert negative exponents carefully.
Why this answer is correct
The correct answer is A. \(\frac{x^{5}}{4}\). Here (\left\(2x^{-3}\right\)^{-2}=2^{-2}x^{6}=\frac{x^{6}}{4}), so multiplying by \(x^{-1}\) gives \(\frac{x^{5}}{4}\). In exams, first convert negative exponents carefully.
Exam Tip
(\left\(2x^{-3}\right\)^{-2}=2^{-2}x^{6}=\frac{x^{6}}{4}), इसलिए \(x^{-1}\) से गुणा करने पर \(\frac{x^{5}}{4}\) मिलता है। परीक्षा में ऋणात्मक घात को पहले धनात्मक रूप में बदलें।
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