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If the identity \\((x+a)^2=x^2-20x+100\\) is true for all \\(x\\), what is the value of \\(a\\)?

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Answer and explanation

Correct answer: \\(-10\\)

Expanding gives \\((x+a)^2=x^2+2ax+a^2\\). Comparing the coefficients of \\(x\\) on both sides, \\(2a=-20\\), so \\(a=-10\\). Substituting this value also gives \\(a^2=100\\), confirming the constant term. Exam tip: For an identity, compare coefficients of like powers of the variable.

Related tags

Quadratic-EquationsIdentitiesCoefficient-ComparisonAlgebraic-ExpansionPolynomials

Frequently asked questions

What is the correct answer to this question?

\\(-10\\)

Why is this the correct answer?

Expanding gives \\((x+a)^2=x^2+2ax+a^2\\). Comparing the coefficients of \\(x\\) on both sides, \\(2a=-20\\), so \\(a=-10\\). Substituting this value also gives \\(a^2=100\\), confirming the constant term. Exam tip: For an identity, compare coefficients of like powers of the variable.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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