If (x=-4) is a root of the equation (2x^2+px-12=0), what is the value of (p)?
Answer and explanation
Correct answer: 5
A given root must make the equation equal to zero. Substituting (x=-4) gives (2(-4)^2+p(-4)-12=0), or (32-4p-12=0). Thus (20-4p=0), so (p=5). Option B results from a sign error and gives (p=-5). Exam tip: Substitute the given root directly into the quadratic equation to find the unknown parameter.
Frequently asked questions
What is the correct answer to this question?
5
Why is this the correct answer?
A given root must make the equation equal to zero. Substituting (x=-4) gives (2(-4)^2+p(-4)-12=0), or (32-4p-12=0). Thus (20-4p=0), so (p=5). Option B results from a sign error and gives (p=-5). Exam tip: Substitute the given root directly into the quadratic equation to find the unknown parameter.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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