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If (x=3) is not a root of (kx^2-8x+5=0), what condition must (k) satisfy?

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Answer and explanation

Correct answer: (k\neq \frac{19}{9})

Putting (x=3), the left side becomes (9k-24+5=9k-19). For it not to be a root, (9k-19\neq0), so (k\neq\frac{19}{9}).

Related tags

Quadratic-EquationsNot-RootParameterExpert

Frequently asked questions

What is the correct answer to this question?

(k\neq \frac{19}{9})

Why is this the correct answer?

Putting (x=3), the left side becomes (9k-24+5=9k-19). For it not to be a root, (9k-19\neq0), so (k\neq\frac{19}{9}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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