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If \(x=-3\) is a root of the equation \(4x^2+px-9=0\), what is the value of \(p\)?
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Answer and explanation
Correct answer: 9
A root must satisfy the equation. Substituting \(x=-3\) gives \(4(-3)^2+p(-3)-9=0\), so \(36-3p-9=0\). Hence, \(27-3p=0\) and \(p=9\). Therefore, option A is correct. Exam tip: Substitute the given root directly into the equation and solve for the unknown parameter.
Frequently asked questions
What is the correct answer to this question?
9
Why is this the correct answer?
A root must satisfy the equation. Substituting \(x=-3\) gives \(4(-3)^2+p(-3)-9=0\), so \(36-3p-9=0\). Hence, \(27-3p=0\) and \(p=9\). Therefore, option A is correct. Exam tip: Substitute the given root directly into the equation and solve for the unknown parameter.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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