If (x^2+bx+49=0) has equal and negative roots, what is the value of (b)?

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Answer and explanation

Correct answer: (14)

For equal roots, (b^2-196=0), so (b=\pm14). The equal root (-\frac{b}{2}) must be negative, hence (b=14).

What is the correct answer to this question?

(14)

Why is this the correct answer?

For equal roots, (b^2-196=0), so (b=\pm14). The equal root (-\frac{b}{2}) must be negative, hence (b=14).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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