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If the roots of (x^2+px+q=0) are (3) and (p), what is a possible value of (p)?
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Answer and explanation
Correct answer: (-\frac{3}{2})
The sum of roots is (3+p), and in the equation the sum is (-p). Thus (3+p=-p), giving (p=-\frac{3}{2}).
Frequently asked questions
What is the correct answer to this question?
(-\frac{3}{2})
Why is this the correct answer?
The sum of roots is (3+p), and in the equation the sum is (-p). Thus (3+p=-p), giving (p=-\frac{3}{2}).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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