If the roots of
(x^2-(m+3)x+18=0)
are
(3)
and
(6)
, what is the value of
(m)
?

6

For a quadratic equation
x^2+bx+c=0
, the sum of the roots is
-b
. Here,
b=-(m+3)
, so the sum of the roots is
m+3
. Since the roots are 3 and 6,
3+6=9=m+3
, giving
m=6
. Option 3 results from mistakenly treating
m+3
as
m
. Exam tip: Verify the result using both the sum of roots and their product;
3\times6=18
matches the constant term.

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.