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If the roots of (x^2-(2k+5)x+(k^2+5k+6)=0) are consecutive integers, what will those roots be?

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Answer and explanation

Correct answer: (k+2) and (k+3)

The sum of roots is (2k+5) and the product is (k^2+5k+6). ((k+2)+(k+3)=2k+5) and ((k+2)(k+3)=k^2+5k+6) are correct.

Related tags

Quadratic-EquationsRootsParameter-PatternExpert

Frequently asked questions

What is the correct answer to this question?

(k+2) and (k+3)

Why is this the correct answer?

The sum of roots is (2k+5) and the product is (k^2+5k+6). ((k+2)+(k+3)=2k+5) and ((k+2)(k+3)=k^2+5k+6) are correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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