If ((t^2-64)x^2+(t-8)x+5=0) is a quadratic equation, what is the correct condition on (t)?

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Correct answer: (t\neq \pm8)

For the equation to be quadratic, the coefficient of (x^2) must not be (0). Here (t^2-64\neq0), so (t\neq\pm8).

What is the correct answer to this question?

(t\neq \pm8)

Why is this the correct answer?

For the equation to be quadratic, the coefficient of (x^2) must not be (0). Here (t^2-64\neq0), so (t\neq\pm8).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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