0 reads0 ratings0 helpful
If the roots of the equation \(x^2+px+q=0\) are \(5\) and \(-2\), what is the value of \(p-q\)?
Advertisement
Answer and explanation
Correct answer: 7
The sum of the roots is \(5+(-2)=3\). Since the sum of roots is \(-p\), we get \(p=-3\). Their product is \(q=5\times(-2)=-10\). Therefore, \(p-q=-3-(-10)=7\). Exam tip: For \(x^2+px+q=0\), the sum of roots is \(-p\) and their product is \(q\).
Frequently asked questions
What is the correct answer to this question?
7
Why is this the correct answer?
The sum of the roots is \(5+(-2)=3\). Since the sum of roots is \(-p\), we get \(p=-3\). Their product is \(q=5\times(-2)=-10\). Therefore, \(p-q=-3-(-10)=7\). Exam tip: For \(x^2+px+q=0\), the sum of roots is \(-p\) and their product is \(q\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement