If \(p(x)=x^2+x\), what is the value of \(p(-1)\)?
Answer and explanation
Correct answer: 0
Substituting \(x=-1\) into the polynomial gives \(p(-1)=(-1)^2+(-1)=1-1=0\). Hence, the correct answer is 0. Option C results from calculating only \((-1)^2=1\) and omitting the \(+x\) term. Exam tip: substitute the given value at every occurrence of \(x\) and carefully handle the sign of a negative number raised to a power.
Frequently asked questions
What is the correct answer to this question?
0
Why is this the correct answer?
Substituting \(x=-1\) into the polynomial gives \(p(-1)=(-1)^2+(-1)=1-1=0\). Hence, the correct answer is 0. Option C results from calculating only \((-1)^2=1\) and omitting the \(+x\) term. Exam tip: substitute the given value at every occurrence of \(x\) and carefully handle the sign of a negative number raised to a power.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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