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If \(p(x)=x^2-4x-12\), what is the value of \(p(6)-p(-2)\)?यदि \(p(x)=x^2-4x-12\) है, तो \(p(6)-p(-2)\) का मान क्या होगा?
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Correct answer:सही उत्तर: 00
The polynomial factors as \(p(x)=(x-6)(x+2)\). Hence, \(p(6)=(6-6)(6+2)=0\) and \(p(-2)=(-2-6)(-2+2)=0\). Therefore, \(p(6)-p(-2)=0-0=0\). Exam tip: evaluate the polynomial at each value separately before finding the difference.बहुपद को \(p(x)=(x-6)(x+2)\) के रूप में लिखा जा सकता है। इसलिए \(p(6)=(6-6)(6+2)=0\) और \(p(-2)=(-2-6)(-2+2)=0\)। अतः \(p(6)-p(-2)=0-0=0\)। परीक्षा-युक्ति: पहले दिए गए मानों को बहुपद में अलग-अलग रखें और फिर अंतर निकालें।
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