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If \(p(x)=x^2+3x-10\), what is the value of \(p(4)-p(-2)\)?यदि \(p(x)=x^2+3x-10\) है, तो \(p(4)-p(-2)\) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 3030
First, \(p(4)=4^2+3(4)-10=16+12-10=18\) and \(p(-2)=(-2)^2+3(-2)-10=4-6-10=-12\). Therefore, \(p(4)-p(-2)=18-(-12)=30\). In such questions, be careful to substitute the negative value with parentheses and remember that subtracting a negative becomes addition.पहले \(p(4)=4^2+3(4)-10=16+12-10=18\) और \(p(-2)=(-2)^2+3(-2)-10=4-6-10=-12\) निकालते हैं। इसलिए \(p(4)-p(-2)=18-(-12)=30\)। ऋणात्मक मान घटाते समय उसके आगे का ऋण चिह्न बदलकर जोड़ना याद रखें।
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