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If (p(x)=x^2-12x+35), what is (\frac{1}{\alpha-1}+\frac{1}{\beta-1}), where (\alpha,\beta) are zeroes?यदि (p(x)=x^2-12x+35), तो (\frac{1}{\alpha-1}+\frac{1}{\beta-1}) क्या है, जहाँ (\alpha,\beta) शून्यक हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{11}{24})(\frac{11}{24})
(\alpha+\beta=12) and (\alpha\beta=35). (\frac{1}{\alpha-1}+\frac{1}{\beta-1}=\frac{\alpha+\beta-2}{\alpha\beta-\alpha-\beta+1}=\frac{10}{24}=\frac{5}{12}).(\alpha+\beta=12) और (\alpha\beta=35) हैं। (\frac{1}{\alpha-1}+\frac{1}{\beta-1}=\frac{\alpha+\beta-2}{\alpha\beta-\alpha-\beta+1}=\frac{10}{24}=\frac{5}{12})।
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