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If the polynomial p(x) = kx³ − 2x² + 5x − 4 satisfies p(1) = 7, what is the value of k?यदि बहुपद p(x) = kx³ − 2x² + 5x − 4 के लिए p(1) = 7 है, तो k का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 88
Substitute x = 1 into the polynomial: p(1) = k − 2 + 5 − 4 = k − 1. Since p(1) = 7, we get k − 1 = 7, so k = 8.बहुपद में x = 1 रखने पर p(1) = k − 2 + 5 − 4 = k − 1 मिलता है। चूँकि p(1) = 7 है, इसलिए k − 1 = 7 और k = 8।
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