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If p(x) = 2x³ + 3x² − 8x + 3, what is the remainder when p(x) is divided by x − 1?यदि p(x) = 2x³ + 3x² − 8x + 3 है, तो p(x) को x − 1 से भाग देने पर शेषफल क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 00
By the Remainder Theorem, the remainder on dividing p(x) by x − 1 is p(1). Substituting x = 1 gives p(1) = 2 + 3 − 8 + 3 = 0, so the remainder is 0.शेषफल प्रमेय के अनुसार, p(x) को x − 1 से भाग देने पर शेषफल p(1) होगा। x = 1 रखने पर p(1) = 2 + 3 − 8 + 3 = 0 मिलता है, इसलिए शेषफल 0 है।
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