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If \(p(x)=2x^2+x-6\), what is the value of \(2p(1)-p(-2)\)?यदि \(p(x)=2x^2+x-6\), तो \(2p(1)-p(-2)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -6-6
First, \(p(1)=2(1)^2+1-6=-3\) and \(p(-2)=2(-2)^2-2-6=0\). Therefore, \(2p(1)-p(-2)=2(-3)-0=-6\), so option A is correct. Exam tip: when substituting \(x=-2\), use parentheses because \((-2)^2=4\), not \(-4\).पहले \(p(1)=2(1)^2+1-6=-3\) और \(p(-2)=2(-2)^2-2-6=0\) ज्ञात करें। अतः \(2p(1)-p(-2)=2(-3)-0=-6\), इसलिए विकल्प A सही है। ध्यान रखें कि \(p(-2)\) निकालते समय \(x=-2\) को पूरे पद में रखने पर \(x^2=4\) होता है।
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