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If in \(2x^2+kx+18=0\), the product of roots is (-3) times the sum of roots, what is (k)?
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Answer and explanation
Correct answer: (6)
The product is (9) and the sum is \(-\frac{k}{2}\). From \(9=-3\left(-\frac{k}{2}\right)\), we get \(k=6\).
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What is the correct answer to this question?
(6)
Why is this the correct answer?
The product is (9) and the sum is \(-\frac{k}{2}\). From \(9=-3\left(-\frac{k}{2}\right)\), we get \(k=6\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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