If (\alpha,\beta) are the roots of (x^2-3x-2=0), which equation has roots (\alpha^2,\beta^2)?
Answer and explanation
Correct answer: (x^2-13x+4=0)
Here (\alpha+\beta=3) and (\alpha\beta=-2). Thus (\alpha^2+\beta^2=13) and (\alpha^2\beta^2=4), so the equation is (x^2-13x+4=0).
Frequently asked questions
What is the correct answer to this question?
(x^2-13x+4=0)
Why is this the correct answer?
Here (\alpha+\beta=3) and (\alpha\beta=-2). Thus (\alpha^2+\beta^2=13) and (\alpha^2\beta^2=4), so the equation is (x^2-13x+4=0).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.
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