If (\alpha,\beta) are roots of (x^2-10x+q=0) and (\alpha^2+\beta^2=58), what is the value of (q)?

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Answer and explanation

Correct answer: (21)

Here (\alpha+\beta=10) and (\alpha\beta=q). Using (\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta), (58=100-2q), so (q=21).

What is the correct answer to this question?

(21)

Why is this the correct answer?

Here (\alpha+\beta=10) and (\alpha\beta=q). Using (\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta), (58=100-2q), so (q=21).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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