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If (\alpha) and (\beta) are zeroes of (3x^2-10x+7), what is the value of (\alpha^2+\beta^2)?यदि (\alpha) और (\beta), (3x^2-10x+7) के शून्यक हैं, तो (\alpha^2+\beta^2) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{58}{9})(\frac{58}{9})
Here (\alpha+\beta=\frac{10}{3}) and (\alpha\beta=\frac{7}{3}). Hence (\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=\frac{100}{9}-\frac{14}{3}=\frac{58}{9}).यहाँ (\alpha+\beta=\frac{10}{3}) और (\alpha\beta=\frac{7}{3}) हैं। इसलिए (\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=\frac{100}{9}-\frac{14}{3}=\frac{58}{9})।
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