यदि \(x^2-8x+15=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\frac{\alpha-1}{\beta-1}+\frac{\beta-1}{\alpha-1}\) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-8x+15=0\), what is the value of \(\frac{\alpha-1}{\beta-1}+\frac{\beta-1}{\alpha-1}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{17}{8}\)

Step 1

Concept

The roots are (3) and (5), so \(\alpha-1\) and \(\beta-1\) are (2) and (4). The value is \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{17}{8}\). The roots are (3) and (5), so \(\alpha-1\) and \(\beta-1\) are (2) and (4). The value is \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\).

Step 3

Exam Tip

मूल (3) और (5) हैं इसलिए \(\alpha-1\) और \(\beta-1\) (2) और (4) होंगे। मान \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-8x+15=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\frac{\alpha-1}{\beta-1}+\frac{\beta-1}{\alpha-1}\) का मान क्या है? / If \(\alpha\) and \(\beta\) are roots of \(x^2-8x+15=0\), what is the value of \(\frac{\alpha-1}{\beta-1}+\frac{\beta-1}{\alpha-1}\)?

Correct Answer: A. \(\frac{17}{8}\). Explanation: मूल (3) और (5) हैं इसलिए \(\alpha-1\) और \(\beta-1\) (2) और (4) होंगे। मान \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\) है। / The roots are (3) and (5), so \(\alpha-1\) and \(\beta-1\) are (2) and (4). The value is \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\).

Which concept should I revise for this Mathematics MCQ?

The roots are (3) and (5), so \(\alpha-1\) and \(\beta-1\) are (2) and (4). The value is \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\).

What exam hint can help solve this Mathematics question?

मूल (3) और (5) हैं इसलिए \(\alpha-1\) और \(\beta-1\) (2) और (4) होंगे। मान \(\frac{2}{4}+\frac{4}{2}=\frac{5}{2}\) है।