यदि \(x^2-7x+10=0\) के मूल \(\alpha\) और \(\beta\) हैं तो (\(\alpha-1\)\(\beta-1\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-7x+10=0\), what is the value of (\(\alpha-1\)\(\beta-1\))?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

Here \(\alpha+\beta=7\) and \(\alpha\beta=10\). (\(\alpha-1\)\(\beta-1\)=10-7+1=4).

Step 2

Why this answer is correct

The correct answer is A. (4). Here \(\alpha+\beta=7\) and \(\alpha\beta=10\). (\(\alpha-1\)\(\beta-1\)=10-7+1=4).

Step 3

Exam Tip

यहां \(\alpha+\beta=7\) और \(\alpha\beta=10\) है। (\(\alpha-1\)\(\beta-1\)=10-7+1=4) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-7x+10=0\) के मूल \(\alpha\) और \(\beta\) हैं तो (\(\alpha-1\)\(\beta-1\)) का मान क्या है? / If \(\alpha\) and \(\beta\) are roots of \(x^2-7x+10=0\), what is the value of (\(\alpha-1\)\(\beta-1\))?

Correct Answer: A. (4). Explanation: यहां \(\alpha+\beta=7\) और \(\alpha\beta=10\) है। (\(\alpha-1\)\(\beta-1\)=10-7+1=4) है। / Here \(\alpha+\beta=7\) and \(\alpha\beta=10\). (\(\alpha-1\)\(\beta-1\)=10-7+1=4).

Which concept should I revise for this Mathematics MCQ?

Here \(\alpha+\beta=7\) and \(\alpha\beta=10\). (\(\alpha-1\)\(\beta-1\)=10-7+1=4).

What exam hint can help solve this Mathematics question?

यहां \(\alpha+\beta=7\) और \(\alpha\beta=10\) है। (\(\alpha-1\)\(\beta-1\)=10-7+1=4) है।