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Class 10 Mathematics Quadratic Equations Roots of a Quadratic EquationHardLevel 32

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If () and () are the roots of (x^2-12x+36=0), what is the value of (-)?

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The quadratic equation (x^2-12x+36=0) factors as ((x-6)^2=0). Hence both roots are 6, so (\alpha=\beta=6) and (\alpha-\beta=6-6=0). Exam tip: when the discriminant (D=b^2-4ac) is zero, the two roots are equal and their difference is zero.

Related tags

Quadratic Equations Roots Equal Roots Discriminant

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Why is this the correct answer?

The quadratic equation (x^2-12x+36=0) factors as ((x-6)^2=0). Hence both roots are 6, so (\alpha=\beta=6) and (\alpha-\beta=6-6=0). Exam tip: when the discriminant (D=b^2-4ac) is zero, the two roots are equal and their difference is zero.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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