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If (\alpha) and (\beta) are roots of (x^2-11x+24=0), what is the value of (\frac{1}{\alpha+1}+\frac{1}{\beta+1})?

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Answer and explanation

Correct answer: (\frac{13}{36})

Here (\alpha+\beta=11) and (\alpha\beta=24). The value is (\frac{\alpha+\beta+2}{\alpha\beta+\alpha+\beta+1}=\frac{13}{36}).

Related tags

RootsReciprocal ShiftedSum Product

Frequently asked questions

What is the correct answer to this question?

(\frac{13}{36})

Why is this the correct answer?

Here (\alpha+\beta=11) and (\alpha\beta=24). The value is (\frac{\alpha+\beta+2}{\alpha\beta+\alpha+\beta+1}=\frac{13}{36}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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