If 5 and 6 are the roots of the equation \(x^2-sx+p=0\), what is the value of \(s+p\)?
Answer and explanation
Correct answer: 41
For the quadratic equation \(x^2-sx+p=0\), the sum of the roots is \(s\), and their product is \(p\). Thus, \(s=5+6=11\) and \(p=5\times6=30\), so \(s+p=11+30=41\). Exam tip: Compare the equation with \(x^2-(\text{sum of roots})x+(\text{product of roots})\) to identify the parameters quickly.
Frequently asked questions
What is the correct answer to this question?
41
Why is this the correct answer?
For the quadratic equation \(x^2-sx+p=0\), the sum of the roots is \(s\), and their product is \(p\). Thus, \(s=5+6=11\) and \(p=5\times6=30\), so \(s+p=11+30=41\). Exam tip: Compare the equation with \(x^2-(\text{sum of roots})x+(\text{product of roots})\) to identify the parameters quickly.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
