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If \(q(x)=x^3-4x^2+x+6\), what is the value of \(q(-1)\)?यदि \(q(x)=x^3-4x^2+x+6\) है, तो \(q(-1)\) का मान क्या होगा?
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Substituting \(x=-1\), we get \(q(-1)=(-1)^3-4(-1)^2+(-1)+6=-1-4-1+6=0\). Here, \((-1)^2=1\) but \((-1)^3=-1\), so the signs must be handled carefully. In an exam, evaluate each term separately before adding them.\(x=-1\) रखने पर \(q(-1)=(-1)^3-4(-1)^2+(-1)+6=-1-4-1+6=0\)। यहाँ \((-1)^2=1\), जबकि \((-1)^3=-1\); इसलिए संकेतों पर विशेष ध्यान दें। परीक्षा में पहले प्रत्येक पद का मान अलग-अलग निकालना उपयोगी रहता है।
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