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Subjects
Class 10MathematicsPolynomialsPolynomials in one variableEasyLevel 48
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For the polynomial \(p(x)=x^2+2x+1\), what is the value of \(p(0)\)?

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Answer and explanation

Correct answer: 1

To find \(p(0)\), substitute \(x=0\): \(p(0)=0^2+2\times0+1=1\). Therefore, the correct answer is 1. Option 2 is incorrect because the term \(2x\) becomes 0 when \(x=0\). Exam tip: To evaluate \(p(a)\), replace every occurrence of \(x\) with \(a\).

Related tags

PolynomialsPolynomial EvaluationConstant TermZero InputEasy

Frequently asked questions

What is the correct answer to this question?

1

Why is this the correct answer?

To find \(p(0)\), substitute \(x=0\): \(p(0)=0^2+2\times0+1=1\). Therefore, the correct answer is 1. Option 2 is incorrect because the term \(2x\) becomes 0 when \(x=0\). Exam tip: To evaluate \(p(a)\), replace every occurrence of \(x\) with \(a\).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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  5. 5If p(x) = x² − 2√2x + 2, which is the correct factorized form of p(x)?
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  10. 10What is the constant term of the polynomial \(7x^2+5x-11\)?
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