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Class 10MathematicsPair of Linear Equations in Two VariablesConditions for solvabilityExpertLevel 59
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For no solution in ((k+1)x+6y=3) and (2x+12y=8), what is (k)?

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Answer and explanation

Correct answer: (k=0)

Equating coefficient ratios gives (k=0). The constant ratio (\frac{3}{8}) is different, so there is no solution.

Related tags

Class10Linear-EquationsSolvability

Frequently asked questions

What is the correct answer to this question?

(k=0)

Why is this the correct answer?

Equating coefficient ratios gives (k=0). The constant ratio (\frac{3}{8}) is different, so there is no solution.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

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10 more MCQs
  1. 1If both lines appear exactly at the same place on the graph, how many solutions will there be?
  2. 2If (a₁/a₂ ≠ b₁/b₂), how will two lines appear on the graph?
  3. 3How many solutions are there for (2x + 5y = 20) and (4x + 10y = 40)?
  4. 4Which pair of equations will give a unique solution?
  5. 5If a₁ = 4, b₁ = 6, c₁ = 10 and a₂ = 2, b₂ = 3, c₂ = 5, how will the lines be related?
  6. 6If a₁ = 6, b₁ = 9, c₁ = 12 and a₂ = 2, b₂ = 3, c₂ = 4, how will the lines be?
  7. 7If a₁ = 7, b₁ = 14, c₁ = 21 and a₂ = 1, b₂ = 2, c₂ = 3, how will the lines be?
  8. 8If the line \(3x+ay=24\) coincides with the line \(3x+4y=24\), what is the value of \(a\)?
  9. 9If the line \(4x+ay=20\) is coincident with the line \(2x+3y=10\), what is the value of \(a\)?
  10. 10What type of lines are 9x − 6y = 21 and 3x − 2y = 7?
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