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For ((k-3)x+2y=5) and (4x+ky=11) to be non-unique, what can (k) be?
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Answer and explanation
Correct answer: (k=\frac{3\pm\sqrt{41}}{2})
For non-unique solutions, the determinant must be zero. From ((k-3)k-8=0), (k=\frac{3\pm\sqrt{41}}{2}).
Frequently asked questions
What is the correct answer to this question?
(k=\frac{3\pm\sqrt{41}}{2})
Why is this the correct answer?
For non-unique solutions, the determinant must be zero. From ((k-3)k-8=0), (k=\frac{3\pm\sqrt{41}}{2}).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.
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