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Choose the correct statement for (15x+10y=5) and (3x+2y=1).

Answer and explanation

Correct answer: There are infinitely many solutions

Every term of the first equation is 5 times the corresponding term of the second: \(15=5\times3\), \(10=5\times2\), and \(5=5\times1\). Thus, both equations represent the same line and have infinitely many common solutions. Therefore, option C is correct. Option A would be correct only if the two lines were distinct and parallel. Exam tip: If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), a pair of linear equations has infinitely many solutions.

Related tags

Linear EquationsConditions For SolvabilityCoincident LinesInfinite SolutionsPair Of Linear Equations In Two VariablesMathematicsClass 10 Mcq

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