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Choose the correct option for (13x+4y=6) and (26x+8y=12).

Answer and explanation

Correct answer: Infinitely many solutions

Here, \(\frac{a_1}{a_2}=\frac{13}{26}=\frac{1}{2}\), \(\frac{b_1}{b_2}=\frac{4}{8}=\frac{1}{2}\), and \(\frac{c_1}{c_2}=\frac{6}{12}=\frac{1}{2}\). Therefore, both equations represent the same line, so the pair has infinitely many solutions. Option B would be correct only if the first two ratios were equal but the third ratio were different. Exam tip: when \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), the pair has infinitely many solutions.

Related tags

Class10Linear EquationsSolvabilityCoincident LinesPair Of EquationsConditions For SolvabilityPair Of Linear Equations In Two VariablesMathematics

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