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What is the value of (a) for the equations (6x+ay=42) and (18x+33y=126) to have infinitely many solutions?

Answer and explanation

Correct answer: 11

For two linear equations to have infinitely many solutions, the condition is \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Here, \(\frac{6}{18}=\frac{42}{126}=\frac{1}{3}\). Therefore, \(\frac{a}{33}=\frac{1}{3}\), giving \(a=11\). Hence, option C is correct. Exam tip: For infinitely many solutions, the ratios of the corresponding coefficients and constant terms must all be equal; checking only one ratio is not sufficient.

Related tags

Linear EquationsInfinitely Many SolutionsSolvability ConditionsParameter ValueClass 10Conditions For SolvabilityPair Of Linear Equations In Two VariablesMathematics

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