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For ((k-3)x+2y=5) and (4x+ky=11) to be non-unique, what can (k) be?युग्म ((k-3)x+2y=5) और (4x+ky=11) अद्वितीय न हो, इसके लिए (k) क्या हो सकता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (k=\frac{3\pm\sqrt{41}}{2})(k=\frac{3\pm\sqrt{41}}{2})
For non-unique solutions, the determinant must be zero. From ((k-3)k-8=0), (k=\frac{3\pm\sqrt{41}}{2}).अद्वितीय न होने के लिए सारणिक शून्य होना चाहिए। ((k-3)k-8=0) से (k=\frac{3\pm\sqrt{41}}{2}) मिलता है।
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