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What will (k) be for (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?समीकरण (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 2828
For two linear equations to have infinitely many solutions, the ratios of their corresponding coefficients and constant terms must be equal: 8/2 = k/7 = 72/18. Since 8/2 and 72/18 are both 4, k/7 = 4, giving k = 28. Therefore, option C is correct. In an exam, check the ratio of the constant terms as well as the variable coefficients.दो रैखिक समीकरणों के अनंत हल होने के लिए उनके संगत गुणांकों और अचर पदों का अनुपात समान होना चाहिए: 8/2 = k/7 = 72/18। यहाँ 8/2 और 72/18 दोनों 4 हैं, इसलिए k/7 = 4 और k = 28। अतः सही विकल्प C है। परीक्षा में केवल चर के गुणांकों का नहीं, बल्कि अचर पदों का अनुपात भी अवश्य जाँचें।
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