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What value of (k) makes (kx+7y=28) and (8x+14y=60) have no solution?

Answer and explanation

Correct answer: 4

A pair of linear equations has no solution when \(a_1/a_2=b_1/b_2\), but this common ratio is not equal to \(c_1/c_2\). Here, \(7/14=1/2\), whereas \(28/60=7/15\), so the constant ratio is different. Thus, \(k/8=1/2\), giving \(k=4\). Exam tip: For inconsistent equations, the coefficient ratios must be equal while the constant ratio must be different.

Related tags

Linear EquationsConditions For SolvabilityNo SolutionParameterPair Of Linear Equations In Two VariablesMathematicsClass 10 Mcq

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