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What is the value of (a) for (6x+ay=30) and (2x+5y=11) to have no solution?

Answer and explanation

Correct answer: 15

Two linear equations have no solution when \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2}\). Here, \(\frac{6}{2}=3\) must equal \(\frac{a}{5}\), so \(\frac{a}{5}=3\) and hence \(a=15\). Also, \(\frac{30}{11}\ne3\), confirming that the two lines are distinct and parallel. Therefore, 15 is correct. Exam tip: equate the ratios of the coefficients first, then verify that the ratio of constants is different.

Related tags

Linear EquationsNo SolutionSolvability ConditionsParallel LinesConditions For SolvabilityPair Of Linear Equations In Two VariablesMathematicsClass 10 Mcq

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