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Which of the following pairs gives no solution?

Answer and explanation

Correct answer: (x+2y=7) and (2x+4y=15)

The direct answer is option B. For equations a1x+b1y=c1 and a2x+b2y=c2, no solution occurs when a1/a2=b1/b2 but c1/c2 is different. In option A, doubling x+2y=7 gives 2x+4y=14, so both equations are the same line and have infinitely many solutions, not none. In option B, the first two coefficient ratios are 1/2=2/4, but the constants give 7/15, which is different. The lines therefore have the same direction but different positions: they are parallel and never meet. Option C has unequal coefficient ratios 1/3 and 2/5, so the lines intersect once. Option D also gives a normal pair: solving 2x-y=3 and x+y=4 gives x=7/3 and y=5/3, so it has one solution. Memory cue: equal coefficient ratios but unequal constant ratio means no solution.

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Linear EquationsMcqNo Solution

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