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Which statement is correct for \(2x+5y=1\) and \(3x+7y=4\)?

Answer and explanation

Correct answer: They have exactly one solution.

Multiply \(2x+5y=1\) by \(3\): \(6x+15y=3\).
Multiply \(3x+7y=4\) by \(2\): \(6x+14y=8\).
Subtract: \((6x+15y)-(6x+14y)=3-8\Rightarrow y=-5\).
Substitute into \(2x+5y=1\): \(2x+5(-5)=1\Rightarrow 2x-25=1\Rightarrow x=13\).
Since we get a definite \((x,y)=(13,-5)\), there is exactly one solution.

Related tags

Pair Of Linear EquationsUnique SolutionElimination MethodConsistency

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