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3 questions tagged with value-practice.

Question 1/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 12

किस संख्या का अभाज्य गुणनखंडन \(2^2 \times 3^2 \times 11\) है?

Which number has prime factorisation \(2^2 \times 3^2 \times 11\)?

Explanation opens after your attempt
Correct Answer

C. 396

Step 1

Concept

\(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4 \times 9 \times 11=36 \times 11=396\).

Step 3

Exam Tip

Evaluating powers first makes the calculation simple. चरण 1: \(2^2=4\) और \(3^2=9\) है। चरण 2: \(4 \times 9 \times 11=36 \times 11=396\)। चरण 3: पहले घातों को हल करना गणना को सरल बनाता है।

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Question 2/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 11

किस संख्या का अभाज्य गुणनखंडन \(2^4 \times 3 \times 5\) है?

Which number has prime factorisation \(2^4 \times 3 \times 5\)?

Explanation opens after your attempt
Correct Answer

C. 240

Step 1

Concept

\(2^4=16\).

Step 2

Why this answer is correct

\(16 \times 3 \times 5=16 \times 15=240\).

Step 3

Exam Tip

Calculate the number yourself before checking the options. चरण 1: \(2^4=16\) होता है। चरण 2: \(16 \times 3 \times 5=16 \times 15=240\)। चरण 3: विकल्पों में जाने से पहले स्वयं संख्या निकालें।

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Question 3/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 10

किस संख्या का अभाज्य गुणनखंडन \(2^3 \times 5^2\) है?

Which number has prime factorisation \(2^3 \times 5^2\)?

Explanation opens after your attempt
Correct Answer

B. 200

Step 1

Concept

\(2^3=8\) and \(5^2=25\).

Step 2

Why this answer is correct

\(8 \times 25=200\), so the number is (200).

Step 3

Exam Tip

Solving powers first makes multiplication simple. चरण 1: \(2^3=8\) और \(5^2=25\) है। चरण 2: \(8 \times 25=200\), इसलिए संख्या (200) है। चरण 3: घातों को पहले हल करने से गुणा सरल हो जाता है।

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