Concept-wise Practice

terminating-result MCQ Questions for Class 10

terminating-result se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with terminating-result.

\(0.\overline{36}\) और \(0.\overline{63}\) का योग किस प्रकार का दशमलव है?

What type of decimal is the sum of \(0.\overline{36}\) and \(0.\overline{63}\)?

Explanation opens after your attempt
Correct Answer

A. सांतTerminating

Step 1

Concept

\(0.\overline{36}=\frac{36}{99}\) and \(0.\overline{63}=\frac{63}{99}\), so their sum is (1). The sum of two recurring decimals can be terminating.

Step 2

Why this answer is correct

The correct answer is A. सांत / Terminating. \(0.\overline{36}=\frac{36}{99}\) and \(0.\overline{63}=\frac{63}{99}\), so their sum is (1). The sum of two recurring decimals can be terminating.

Step 3

Exam Tip

\(0.\overline{36}=\frac{36}{99}\) और \(0.\overline{63}=\frac{63}{99}\) हैं इसलिए योग (1) है। दो आवर्ती दशमलवों का योग सांत भी हो सकता है।

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\(0.\overline{27}\) और \(0.\overline{72}\) का योग किस प्रकार का दशमलव है?

What type of decimal is the sum of \(0.\overline{27}\) and \(0.\overline{72}\)?

Explanation opens after your attempt
Correct Answer

A. सांतTerminating

Step 1

Concept

\(0.\overline{27}=\frac{27}{99}\) and \(0.\overline{72}=\frac{72}{99}\), so their sum is (1). The sum of two recurring decimals can be terminating.

Step 2

Why this answer is correct

The correct answer is A. सांत / Terminating. \(0.\overline{27}=\frac{27}{99}\) and \(0.\overline{72}=\frac{72}{99}\), so their sum is (1). The sum of two recurring decimals can be terminating.

Step 3

Exam Tip

\(0.\overline{27}=\frac{27}{99}\) और \(0.\overline{72}=\frac{72}{99}\) हैं इसलिए योग (1) है। दो आवर्ती दशमलवों का योग सांत भी हो सकता है।

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\(0.\overline{54}\) और \(0.\overline{45}\) का योग किस प्रकार का दशमलव है?

What type of decimal is the sum of \(0.\overline{54}\) and \(0.\overline{45}\)?

Explanation opens after your attempt
Correct Answer

A. सांतTerminating

Step 1

Concept

\(0.\overline{54}=\frac{54}{99}\) and \(0.\overline{45}=\frac{45}{99}\), so their sum is (1). The sum of two recurring decimals can sometimes be terminating.

Step 2

Why this answer is correct

The correct answer is A. सांत / Terminating. \(0.\overline{54}=\frac{54}{99}\) and \(0.\overline{45}=\frac{45}{99}\), so their sum is (1). The sum of two recurring decimals can sometimes be terminating.

Step 3

Exam Tip

\(0.\overline{54}=\frac{54}{99}\) और \(0.\overline{45}=\frac{45}{99}\), इसलिए योग (1) है। दो आवर्ती दशमलवों का योग कभी-कभी सांत हो सकता है।

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