Concept-wise Practice

prime-factor-frequency MCQ Questions for Class 10

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Practice Questions

3 questions tagged with prime-factor-frequency.

Question 1/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 12

\(2^4 \times 3 \times 5^2\) में कुल अभाज्य गुणनखंडों की आवृत्ति कितनी है?

What is the total frequency of prime factors in \(2^4 \times 3 \times 5^2\)?

Explanation opens after your attempt
Correct Answer

C. 7

Step 1

Concept

Total frequency is found by adding the exponents.

Step 2

Why this answer is correct

The exponents are (4,1,2), so the total is (4+1+2=7).

Step 3

Exam Tip

If no exponent is shown, take it as (1). चरण 1: कुल आवृत्ति घातों के योग से मिलती है। चरण 2: घातें (4,1,2) हैं, इसलिए कुल (4+1+2=7) है। चरण 3: जहां घात नहीं दिखती, वहां घात (1) मानी जाती है।

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Question 2/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 11

\(2^3 \times 3 \times 5^2\) में कुल अभाज्य गुणनखंडों की आवृत्ति कितनी है?

What is the total frequency of prime factors in \(2^3 \times 3 \times 5^2\)?

Explanation opens after your attempt
Correct Answer

C. 6

Step 1

Concept

Total frequency is found by adding the exponents.

Step 2

Why this answer is correct

The exponents are (3,1,2), so the total is (3+1+2=6).

Step 3

Exam Tip

If no exponent is written, treat it as (1). चरण 1: कुल आवृत्ति घातों के योग से मिलती है। चरण 2: यहां घातें (3,1,2) हैं, इसलिए कुल (3+1+2=6) है। चरण 3: जहां घात नहीं लिखी होती, वहां घात (1) मानी जाती है।

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Question 3/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 10

\(2^2 \times 3 \times 5^2\) में कुल अभाज्य गुणनखंडों की आवृत्ति कितनी है?

What is the total frequency of prime factors in \(2^2 \times 3 \times 5^2\)?

Explanation opens after your attempt
Correct Answer

C. 5

Step 1

Concept

Add the exponents to find the total frequency of prime factors.

Step 2

Why this answer is correct

The exponents are (2,1,2), so the total is (2+1+2=5).

Step 3

Exam Tip

When no exponent is written, treat it as (1). चरण 1: कुल आवृत्ति जानने के लिए घातों को जोड़ते हैं। चरण 2: घातें (2,1,2) हैं, इसलिए कुल (2+1+2=5) है। चरण 3: जहां घात नहीं लिखी होती, वहां घात (1) मानी जाती है।

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