यदि \(x=\sqrt{2}+\sqrt{5}\), तो (x) किस द्विघात समीकरण को संतुष्ट करता है?
If \(x=\sqrt{2}+\sqrt{5}\), which quadratic equation is satisfied by (x)?
Explanation opens after your attempt
Correct Answer
B. \(x^4-14x^2+9=0\)
Concept
From \(x^2=7+2\sqrt{10}\), we get (\(x^2-7\)2=40). Hence \(x^4-14x^2+9=0\).
Why this answer is correct
The correct answer is B. \(x^4-14x^2+9=0\). From \(x^2=7+2\sqrt{10}\), we get (\(x^2-7\)2=40). Hence \(x^4-14x^2+9=0\).
Exam Tip
\(x^2=7+2\sqrt{10}\) से (\(x^2-7\)2=40) मिलता है। इसलिए \(x^4-14x^2+9=0\) है।
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