Since \(2<\sqrt{7}<3\), we have \(-3<-\sqrt{7}<-2\). For negative numbers, remember the order reverses.
Step 2
Why this answer is correct
The correct answer is A. ( -3) और (-2) / ( -3) and (-2). Since \(2<\sqrt{7}<3\), we have \(-3<-\sqrt{7}<-2\). For negative numbers, remember the order reverses.
Step 3
Exam Tip
क्योंकि \(2<\sqrt{7}<3\), इसलिए \(-3<-\sqrt{7}<-2\)। ऋणात्मक संख्या में क्रम उलटने पर ध्यान रखें।
\(-\sqrt{25}=-5\) and \(-\sqrt{36}=-6\), so (-5) is to the right. Among negatives, the one with smaller magnitude is greater.
Step 2
Why this answer is correct
The correct answer is A. \(-\sqrt{25}\). \(-\sqrt{25}=-5\) and \(-\sqrt{36}=-6\), so (-5) is to the right. Among negatives, the one with smaller magnitude is greater.
Step 3
Exam Tip
\(-\sqrt{25}=-5\) और \(-\sqrt{36}=-6\), इसलिए (-5) दाईं ओर है। ऋणात्मक संख्याओं में कम परिमाण वाली संख्या बड़ी होती है।
The sum (-4) is already negative and the product must be positive, so (c>0). For real roots, \(16-4c\ge0\), hence \(0<c\le4\).
Step 2
Why this answer is correct
The correct answer is A. \(0<c\le4\). The sum (-4) is already negative and the product must be positive, so (c>0). For real roots, \(16-4c\ge0\), hence \(0<c\le4\).
Step 3
Exam Tip
योग (-4) पहले से ऋणात्मक है और गुणनफल धनात्मक चाहिए, इसलिए (c>0)। वास्तविक जड़ों के लिए \(16-4c\ge0\), अतः \(0<c\le4\)।
