यदि \(x^2+10x+21=0\) की जड़ें \(\alpha,\beta\) हैं, तो (\(\alpha-\beta\)2+4\alpha\beta) का मान क्या है?
If \(\alpha,\beta\) are roots of \(x^2+10x+21=0\), what is (\(\alpha-\beta\)2+4\alpha\beta)?
Explanation opens after your attempt
A. (100)
Concept
We know (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta). Hence (\(\alpha-\beta\)2+4\alpha\beta=\(\alpha+\beta\)2=100).
Why this answer is correct
The correct answer is A. (100). We know (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta). Hence (\(\alpha-\beta\)2+4\alpha\beta=\(\alpha+\beta\)2=100).
Exam Tip
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta) होता है। इसलिए (\(\alpha-\beta\)2+4\alpha\beta=\(\alpha+\beta\)2=100)।
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