The difference between the two angles is \(4\pi\), which is a multiple of \(2\pi\). Therefore, they are coterminal.
Step 2
Why this answer is correct
The correct answer is D. वे सह-प्रारंभिक हैं / They are coterminal. The difference between the two angles is \(4\pi\), which is a multiple of \(2\pi\). Therefore, they are coterminal.
Step 3
Exam Tip
दोनों कोणों का अंतर \(4\pi\) है, जो \(2\pi\) का गुणज है। इसलिए वे सह-प्रारंभिक हैं।
\(\frac{58\pi}{9}-6\pi=\frac{4\pi}{9}\). In exams, subtract multiples of \(2\pi\) to keep the angle in the interval.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{4\pi}{9}\). \(\frac{58\pi}{9}-6\pi=\frac{4\pi}{9}\). In exams, subtract multiples of \(2\pi\) to keep the angle in the interval.
Step 3
Exam Tip
\(\frac{58\pi}{9}-6\pi=\frac{4\pi}{9}\)। परीक्षा में \(2\pi\) के गुणज घटाकर अंतराल में कोण रखें।
One complete revolution is \(360^\circ\) and \(\frac{1440^\circ}{360^\circ}=4\). In exams, divide the difference by \(360^\circ\).
Step 2
Why this answer is correct
The correct answer is B. (4). One complete revolution is \(360^\circ\) and \(\frac{1440^\circ}{360^\circ}=4\). In exams, divide the difference by \(360^\circ\).
Step 3
Exam Tip
एक पूर्ण चक्कर \(360^\circ\) होता है और \(\frac{1440^\circ}{360^\circ}=4\)। परीक्षा में अंतर को \(360^\circ\) से भाग दें।
\(-1540^\circ+1800^\circ=260^\circ\), so the principal coterminal angle is \(260^\circ\). In exams, add multiples of \(360^\circ\) to negative angles.
Step 2
Why this answer is correct
The correct answer is A. \(260^\circ\). \(-1540^\circ+1800^\circ=260^\circ\), so the principal coterminal angle is \(260^\circ\). In exams, add multiples of \(360^\circ\) to negative angles.
Step 3
Exam Tip
\(-1540^\circ+1800^\circ=260^\circ\), इसलिए मुख्य सह-प्रारंभिक कोण \(260^\circ\) है। परीक्षा में ऋणात्मक कोण में \(360^\circ\) के गुणज जोड़ें।
Adding \(6\pi\) to \(-\frac{31\pi}{6}\) gives \(\frac{5\pi}{6}\). In exams, add multiples of \(2\pi\) to negative angles.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{5\pi}{6}\). Adding \(6\pi\) to \(-\frac{31\pi}{6}\) gives \(\frac{5\pi}{6}\). In exams, add multiples of \(2\pi\) to negative angles.
Step 3
Exam Tip
\(-\frac{31\pi}{6}\) में \(6\pi\) जोड़ने पर \(\frac{5\pi}{6}\) मिलता है। परीक्षा में ऋणात्मक कोण में \(2\pi\) के गुणज जोड़ें।
\(0^\circ\) and \(360^\circ\) have the same terminal side so they are coterminal. Look for a difference of \(360^\circ\).
Step 2
Why this answer is correct
The correct answer is C. सहसमापी कोण / Coterminal angles. \(0^\circ\) and \(360^\circ\) have the same terminal side so they are coterminal. Look for a difference of \(360^\circ\).
Step 3
Exam Tip
\(0^\circ\) और \(360^\circ\) की अंतिम भुजा समान होती है इसलिए वे सहसमापी हैं। \(360^\circ\) के अंतर को पहचानें।
The difference between coterminal angles is an integral multiple of \(360^\circ\). Use this rule when the terminal side is the same.
Step 2
Why this answer is correct
The correct answer is D. \(360^\circ\). The difference between coterminal angles is an integral multiple of \(360^\circ\). Use this rule when the terminal side is the same.
Step 3
Exam Tip
सह-अंतिम कोणों में अंतर \(360^\circ\) के पूर्णांक गुणज का होता है। अंतिम भुजा समान हो तो यह नियम लगाएं।
